Uri - Beecrowd | 1067 | Odd Numbers

 | 1067

Odd Numbers

Adapted by Neilor Tonin, URI Brazil

Read an integer value X (1 <= X <= 1000).  Then print the odd numbers from 1 to X, each one in a line, including X if is the case.

Input

The input will be an integer value.

Output

Print all odd values between 1 and X, including X if is the case.

Input Sample	Output Sample
8	1 3 5 7

N.B.: It's better if you solve this by your own. Thank you!

  URI - BEECROWD Online Judge 1067 Solve  in C :                                          

//Solved by Intesar
#include <stdio.h>
int main() {
    int x,i;
    scanf("%d",&x);
    for(i=1;i<=x;i++)
    {
        if(i%2!=0)
            printf("%d\n",i);
    }
    return 0;
}